What is the Terminal Velocity of a Bowling Ball?
In fluid dynamics, terminal velocity refers to the constant speed at which an object falling through a fluid (such as air or water) reaches when the drag force acting on the object equals its weight.
Calculating Terminal Velocity
The terminal velocity of a bowling ball can be calculated using the following formula:
Vt = √(2mg / ρACd)
where:
- Vt is the terminal velocity
- m is the mass of the bowling ball
- g is the acceleration due to gravity
- ρ is the density of the fluid (air in this case)
- A is the cross-sectional area of the bowling ball
- Cd is the drag coefficient
Factors Affecting Terminal Velocity
Several factors influence the terminal velocity of a bowling ball, including:
- Mass: Heavier balls have a higher terminal velocity.
- Shape: A ball's aerodynamic shape affects its drag coefficient, which in turn influences its terminal velocity.
- Fluid Density: A ball's terminal velocity is lower in denser fluids (e.g., water) compared to less dense fluids (e.g., air).
Typical Terminal Velocity
The typical terminal velocity of a bowling ball falling through air is approximately 20 mph (32 km/h).
Related Questions
- What other factors can affect the terminal velocity of an object?
- Why do objects with a higher drag coefficient have a lower terminal velocity?
- How can you increase the terminal velocity of a bowling ball?
- What is the difference between terminal velocity and escape velocity?
- What is the terminal velocity of a golf ball?
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