How Much Would a Solid Gold Statue the Size of a 6 Foot Person Cost?
The cost of a solid gold statue the size of a 6-foot person would be astronomical. Gold is a precious metal, and its price fluctuates depending on market conditions. However, at the time of writing, the spot price of gold is approximately \$1,900 per troy ounce.
A 6-foot person would weigh approximately 150 pounds. This means that a solid gold statue of a 6-foot person would weigh approximately 1,200 troy ounces. At \$1,900 per troy ounce, the gold alone would cost approximately \$2.28 million.
In addition to the cost of the gold, there would also be the cost of casting and finishing the statue. These costs would vary depending on the complexity of the design and the skill of the artisans involved. However, it is reasonable to estimate that the total cost of a solid gold statue of a 6-foot person would be in the region of \$3 million or more.
Related Questions
- How much does a 1-foot gold statue cost? Approximately \$190,000.
- How much does a 100-pound gold bar cost? Approximately \$2 million.
- What is the most expensive statue in the world? The Statue of Unity in India, which cost \$290 million.
- What is the tallest gold statue in the world? The Great Buddha of Thailand, which is 92 feet tall.
- Can you buy a solid gold statue? Yes, but it would be very expensive.
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