How many gallons of water are in a 27 foot round pool 52 inches deep?
To calculate the number of gallons of water in a 27-foot round pool 52 inches deep, we need to determine the volume of the pool in cubic feet and then convert it to gallons.
Step 1: Calculate the Volume
The volume of a cylinder is given by the formula:
V = πr²h
where:
- V is the volume in cubic feet
- π is a mathematical constant approximately equal to 3.14
- r is the radius of the pool in feet
- h is the height of the pool in feet
In this case, the radius of the pool is 27 feet / 2 = 13.5 feet, and the height is 52 inches / 12 = 4.33 feet. Plugging these values into the formula, we get:
V = π(13.5)²(4.33) ≈ 2,348.6 cubic feet
Step 2: Convert to Gallons
There are 7.48 gallons in a cubic foot. Therefore, the number of gallons of water in the pool is:
2,348.6 cubic feet * 7.48 gallons/cubic foot ≈ 17,600 gallons
Conclusion
A 27-foot round pool 52 inches deep holds approximately 17,600 gallons of water.
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