A Baseball Diamond Is a Square That Is 90 Feet on Each Side. What Is the Distance a Catcher Has to Throw the Ball from Home to Second Base?
In baseball, the distance from home plate to second base is 127 feet and 3 3/8 inches (38.71 meters). This measurement is taken along the diagonal of the square that forms the infield, which is 90 feet on each side, including the foul lines.
To calculate this distance, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. In this case, the hypotenuse is the diagonal from home plate to second base, and the other two sides are the 90-foot lines from home plate to first base and from first base to second base.
Diagonal² = 90² + 90²
Diagonal² = 8100 + 8100
Diagonal² = 16200
Diagonal = √16200
Diagonal = 127.33 feet
Therefore, the distance a catcher has to throw the ball from home to second base is 127 feet and 3 3/8 inches.
Related Questions
- What is the shape of a baseball diamond? A square.
- How long is each side of a baseball diamond? 90 feet.
- How far is it from home plate to first base? 90 feet.
- How far is it from first base to second base? 90 feet.
- How far is it from second base to third base? 90 feet.
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