A Farmer Plans to Build a Triangular Fence with Side Lengths of 500 m, 461 m, and 408 m. What Are the Measures of the Angles?

The Law of Cosines states that in a triangle with sides of length a, b, and c and opposite angles A, B, and C, the following equation holds:

c^2 = a^2 + b^2 - 2ab cos(C)

Using this law, we can solve for the angles of the triangle. Let's label the sides as follows:

a = 500 m b = 461 m c = 408 m

We can use the Law of Cosines to solve for the angle C opposite side c:

408^2 = 500^2 + 461^2 - 2(500)(461) cos(C)

Solving for C, we get:

C = 104.4 degrees

We can then use the Law of Sines to solve for the other angles:

sin(A)/a = sin(C)/c

Solving for A, we get:

A = 42.8 degrees

Similarly, we can solve for B:

B = 32.8 degrees

Therefore, the measures of the angles of the triangle are:

  • Angle A: 42.8 degrees
  • Angle B: 32.8 degrees
  • Angle C: 104.4 degrees
  1. What is the perimeter of the triangle?
  2. What is the area of the triangle?
  3. What is the length of the longest side of the triangle?
  4. What is the measure of the smallest angle in the triangle?
  5. What theorem can be used to solve for the angles of the triangle?
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