Probability of Selecting a Left-Handed Player in a Tennis Club
A tennis club has 4 left-handed players and 9 right-handed players. If 2 players are randomly selected for a practice game, what is the probability that at least one of them is left-handed?
Calculation:
To determine the probability, we need to consider two cases:
- Both players are left-handed:
Number of ways to select 2 left-handed players from 4: C(4, 2) = 6 Probability: (6 / 13) x (5 / 12) = 15/78
- One player is left-handed and one player is right-handed:
Number of ways to select 1 left-handed player from 4: C(4, 1) = 4 Number of ways to select 1 right-handed player from 9: C(9, 1) = 9 Probability: (4 / 13) x (9 / 12) x 2 = 27/39
Total Probability:
Adding the probabilities of both cases: 15/78 + 27/39 = 57/78
Therefore, the probability that at least one of the two players selected is left-handed is 57/78 or approximately 0.73.
Related Questions:
- What is the probability that both players are right-handed?
- What is the probability that the first player selected is left-handed?
- What is the probability that the second player selected is left-handed?
- What is the expected number of left-handed players selected?
- What is the probability that neither player is left-handed?
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